MCQ
The plot of $\log\,K$ Vs $\frac{1}{T}$ helps to calculate
- AThe energy of activation
- BThe rate constant of the reaction
- CThe order of reaction
- ✓The energy of activation as well as frequency factor
$\log k=\log A-\frac{E_a}{2.303} \cdot \frac{1}{T}$
Plot of $\log k\,vs\, \frac{1}{ T }$ is a straight line.
Slope $=-\frac{ E _{ a }}{2.303 R }$
Intercept $=\log A$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\operatorname{P} t|{H_{{2_{\left( {2\,atm} \right)}}}}|H_{\left( {0.002\,M} \right)}^ \oplus ||H_{\left( {0.1\,M} \right)}^ \oplus |{H_{{2_{\left( {1\,atm} \right)}}}}|Pt$
$E _{ FeO _4^{2-} / Fe ^{2+}}^\theta$ is $x \times 10^{-3} V$. The value of $x$ is $.........$.