STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — JEE STD 11 Science — Question

$\quad\quad\quad\quad H _2 O == CH ^{+}+{ }^{-} OH$

At $pOH\quad\,7 \quad\quad\quad 10^{-7} \quad\quad 10^{-7}$

If $pOH =14 \rightarrow$ solution is highly basic, the conc. of $- OH$ will be very high and due to common ion effect, the reaction goes back ward and $\alpha$ will decrease.

If $pOH =0 \rightarrow$ solution is highly aicidic, the concentration of $H ^{+}$ will be very high and due to common ion effect, the reaction moves in back ward direction.

$\therefore \quad$ At $pOH =7$, maximum dissociation.