MCQ
The $pOH$ at which water is maximum dissociated at $25\,^oC,$ is
- A$14$
- ✓$7$
- C$0$
- DNone of these
$\quad\quad\quad\quad H _2 O == CH ^{+}+{ }^{-} OH$
At $pOH\quad\,7 \quad\quad\quad 10^{-7} \quad\quad 10^{-7}$
If $pOH =14 \rightarrow$ solution is highly basic, the conc. of $- OH$ will be very high and due to common ion effect, the reaction goes back ward and $\alpha$ will decrease.
If $pOH =0 \rightarrow$ solution is highly aicidic, the concentration of $H ^{+}$ will be very high and due to common ion effect, the reaction moves in back ward direction.
$\therefore \quad$ At $pOH =7$, maximum dissociation.
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${H_2}O(g) + C(s) \to CO(g) + {H_2}(g);\,\Delta H = 131\,kJ$$CO(g) + \frac{1}{2}{O_2}(g) \to C{O_2}(g);\Delta H = - 282\,kJ$
${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(g);\,\Delta H = - 242\,kJ$
$C(s) + {O_2}(g) \to C{O_2}(g);\,\Delta H = X\,kJ$ The value of $X$ is ......$kJ$
Reason : $1-$ Butene is more stable than $2-$ butene According to Saytzeff's rule, $2-$ butene should be the product which is more branched or substituted compound and hence, more stable than butene $-1$