MCQ
The potassium ferrocyanide solution gives Prussian blue colour, when added to :
- A$\mathrm{CoCl}_{3}$
- B$\mathrm{FeCl}_{2}$
- C$\mathrm{CoCl}_{2}$
- ✓$\mathrm{FeCl}_{3}$
$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$Prussian blue
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$C{{H}_{3}}-C\equiv CH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}A\xrightarrow{NaB{{H}_{4}}}B$
Reactent $(A)$ is
[At $45^{\circ} \mathrm{C}$ vapour pressure of benzene is $280\, \mathrm{~mm} \,\mathrm{Hg}$ and that of octane is $420\, \mathrm{~mm} \,\mathrm{Hg}$. Assume Ideal gas]
