Incident wavelength, $\lambda=200\, \mathrm{nm}$
Work function, $\phi_{0}=5.01 \,\mathrm{eV}$
According to Einstein's photoelectric equation
${e V_{s}=h v-\phi_{0}}$
${e V_{s}=\frac{h c}{\lambda}-\phi_{0}}$
where $V_{s}$ is the stopping potential
$e V_{s}=\frac{(1240 \,\mathrm{eV} \mathrm{nm})}{(200\, \mathrm{nm})}-5.01 \,\mathrm{eV}$
$=6.2\, \mathrm{eV}-5.01\, \mathrm{eV}=1.2\, \mathrm{eV}$
Stopping potential, $V_{s}=1.2 \,\mathrm{V}$
The potential difference that must be applied to stop photoelectrons $=-\,V_{s}=-\,1.2\, \mathrm{V}$
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