MCQ
The prefix zepto stands for
- A${10^9}$
- B${10^{ - 12}}$
- C${10^{ - 15}}$
- ✓${10^{ - 21}}$
✓
Answer
Correct option: D.
${10^{ - 21}}$
d
Zepto is a unit prefix in the metric system denoting a factor of $10^{-21}$.
Zepto is a unit prefix in the metric system denoting a factor of $10^{-21}$.
$1$ zepto $ = {10^{ - 21}}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In Kjeldahl’s method for estimation of nitrogen, $C_uSO_4$ acts as :
→The outer orbitals of $C$ in ethene molecule can be considered to be hybridized to give three equivalent $sp^2$ orbitals. The total number of sigma $(\sigma )$ and pi $(\pi )$ bonds in ethene molecule is
→Which of the following solutions has the highest $pH$ ?
→→
The major product $[B]$ in the following sequence of reactions is
→$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - C{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{CH{{(C{H_3})}_2}\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{(ii)\,{H_2}{O_2},O{H^ - }}]{{(i)\,{B_2}{H_6}}}[A]$$\xrightarrow[\Delta ]{{dil.\,{H_2}S{O_4}}}[B]$
$C{H_3}CH = CHCHO$ is oxidised to $C{H_3}CH = CHCOOH$ using
→Given below are two statements : One is labelled as Assertion $A$ and the other is labelled as Reason $R:$
Assertion $A :$ The stability order of $+1$ oxidation state of $Ga,$ In and $Tl$ is $Ga < In < Tl.$
Reason $R :$ The inert pair effect stabilizes the
lower oxidation state down the group. In the light of the above statements, choose the correct answer from the options given below :
→Assertion $A :$ The stability order of $+1$ oxidation state of $Ga,$ In and $Tl$ is $Ga < In < Tl.$
Reason $R :$ The inert pair effect stabilizes the
lower oxidation state down the group. In the light of the above statements, choose the correct answer from the options given below :
Identify the homoleptic complex(es) that is/are low spin.
(A) $\left[ Fe ( CN )_5 NO \right]^{2-}$
(B) $\left[ CoF _6\right]^{3-}$
(C) $\left[ Fe ( CN )_6\right]^{+}$
(D) $\left[ Co \left( NH _3\right)_6\right]^{3+}$
(E) $\left[ Cr \left( H _2 O \right)_6\right]^{2+}$
Choose the correct answer from the options given below :
→(A) $\left[ Fe ( CN )_5 NO \right]^{2-}$
(B) $\left[ CoF _6\right]^{3-}$
(C) $\left[ Fe ( CN )_6\right]^{+}$
(D) $\left[ Co \left( NH _3\right)_6\right]^{3+}$
(E) $\left[ Cr \left( H _2 O \right)_6\right]^{2+}$
Choose the correct answer from the options given below :
Which of the following is optically active
Consider the half-cell reduction reaction
→$Mn^{2+} + 2e^- \rightarrow Mn,\, $$E^o = - 1.18\, V$
$Mn^{2+} \rightarrow Mn^{3+} + e^-,$ $ E^o = - 1.51 \,V$
The $E^o$ for the reaction $3Mn^{2+} \rightarrow Mn^o + 2Mn^{3+},$
and possibility of the forward reaction are respectively