MCQ
The present atomic weight scale is based on
- ✓${C^{12}}$
- B${O^{16}}$
- C${H^1}$
- D${C^{13}}$
The atomic mass is very small in the numerical values that's why it is calculated on the basis of comparison with the mass of carbon-$12$ isotope.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Where $D$ is an isotope of hydrogen
$CaC{O_3}\left( s \right)\overset \Delta \longleftrightarrow CaO\left( s \right) + C{O_2} \uparrow ,{K_p} = 8 \times {10^{ - 2}}$
$C{O_2}\left( g \right) + C\left( s \right) \rightleftharpoons 2CO\left( g \right),{K_p} = 2$

| Column-$I$ | Column-$II$ (Shape) |
| $(A) \,SF_4$ | $(1)$ Tetrahedral |
| $(B)\, BrF_3$ | $(2)$ Pyramidal |
| $(C)\, BrO_3^-$ | $(3)$ Sea-Saw shaped |
| $(D)\, NH_4^+$ | $(4)$ Bent $T-$ shaped |