Question
The probability distribution of a random variable $X$ is as follows:
$P ( x )= \begin{cases}0.16 & x=0 \\ 0.12 & x=1 \\ 0.12(5-x) & x=2,3,4\end{cases}$
Find $E(X)$.
$P ( x )= \begin{cases}0.16 & x=0 \\ 0.12 & x=1 \\ 0.12(5-x) & x=2,3,4\end{cases}$
Find $E(X)$.