MCQ
The product obtained by heating ${(N{H_4})_2}S{O_4}$ and $KCNO$ is
- AHydrocyanic acid
- BAmmonia
- CAmmonium cyanide
- ✓Urea
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${N_2}(g)\, + \,{O_2}(g)\,\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}\,2NO(g)$
$C_0=Ce^{-2.1 \times 10^{-3}t}$ for the forward reaction and $C'_0=C'e^{-4.2 \times 10^{-4}t}$ for the backward reaction, hence $K_c$ for the above equilibrium is :-
| Name according to IUPAC nomenclature | IUPAC offficial Name |
| (A) Ununoctium | Oganesson |
| (B) Ununnillium | Darmstadtium |
| (C) Unniltrium | Lawrencium |
| (D) Unnilseptium | Dubnium |
$Benzene$ $\xrightarrow{HCHO+HCl}\,A$$\xrightarrow{AgCN}\,B$

${\text{Propanoic acid }}\xrightarrow{{SOC{l_2}}}X\xrightarrow{{N{H_3}}}Y\xrightarrow{{B{r_2} + KOH}}Z$
What is the compound $Z$