MCQ
The quadratic equation whose one root is $\frac{1}{{2 + \sqrt 5 }}$ will be
  • ${x^2} + 4x - 1 = 0$
  • B
    ${x^2} + 4x + 1 = 0$
  • C
    ${x^2} - 4x - 1 = 0$
  • D
    $\sqrt 2 {x^2} - 4x + 1 = 0$

Answer

Correct option: A.
${x^2} + 4x - 1 = 0$
a
(a) Let $\alpha = \frac{1}{{2 + \sqrt 5 }}$and $\beta = \frac{1}{{2 - \sqrt 5 }}$

Sum of roots $\alpha + \beta = - 4$ and product of roots $\alpha \beta = - 1$

Thus required equation is ${x^2} + 4x - 1 = 0$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If square root of, ${a^{\frac{1}{a}}}.{(2a)^{\frac{1}{{2a}}}}.{(4a)^{\frac{1}{{4a}}}}.{(8a)^{\frac{1}{{8a}}}}........\infty $ is $\frac{8}{{27}}$ , then the value of $'a'$ is

 

The position vectors of the vertices $A, B$ and $C$ of a triangle are $2 \hat{i}-3 \hat{j}+3 \hat{k}, \quad 2 \hat{i}+2 \hat{j}+3 \hat{k} \quad$ and $-\hat{i}+\hat{j}+3 \hat{k}$ respectively. Let $l$ denotes the length of the angle bisector $\mathrm{AD}$ of $\angle \mathrm{BAC}$ where $\mathrm{D}$ is on the line segment $\mathrm{BC}$, then $2 l^2$ equals:
If $A = \left[ {\begin{array}{*{20}{c}}1&2&3\\5&0&7\\6&2&5\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}1&3&5\\0&0&2\end{array}} \right]$, then which of the following is defined
$\frac{{\cos 9^\circ + \sin 9^\circ }}{{\cos 9^\circ - \sin 9^\circ }} = $
Let $f:[0,2] \rightarrow R$ be the function defined by

$f ( x )=(3-\sin (2 \pi x )) \sin \left(\pi x -\frac{\pi}{4}\right)-\sin \left(3 \pi x +\frac{\pi}{4}\right)$

If $\alpha, \beta \in[0,2]$ are such that $\{x \in[0,2]: f(x) \geq 0\}=[\alpha, \beta]$, then the value of $\beta-\alpha$ is. . . . . . . . . 

The value of $\int\limits_{ - \pi /2}^{\pi /2} {\frac{{{{\sin }^2}\,x}}{{1 + {2^x}}}dx} $ is
Let $y\,(x)$ be a solution of $\frac{{(2 + \sin \,x)\,dy}}{{(1 + y)dx}} = \cos \,\,x.$ If $y(0) = 2,$ then $y\left( {\frac{\pi }{2}} \right)$ equals
$\int_{\,0}^{\,\infty } {\,\log \left( {x + \frac{1}{x}} \right)\frac{{dx}}{{1 + {x^2}}}} $ is equal to
A point $z$ moves on Argand diagram in such a way that $|z -3i|$ $ = 2,$ then its locus will be
In a class of $55$ students, the number of students studying different subjects are $23$ in Mathematics, $24$ in Physics, $19$ in Chemistry, $12$ in Mathematics and Physics, $9$ in Mathematics and Chemistry, $7$ in Physics and Chemistry and $4$ in all the three subjects. The total numbers of students who have taken exactly one subject is