MCQ
The quadratic equation whose one root is $\frac{1}{{2 + \sqrt 5 }}$ will be
- ✓${x^2} + 4x - 1 = 0$
- B${x^2} + 4x + 1 = 0$
- C${x^2} - 4x - 1 = 0$
- D$\sqrt 2 {x^2} - 4x + 1 = 0$
Sum of roots $\alpha + \beta = - 4$ and product of roots $\alpha \beta = - 1$
Thus required equation is ${x^2} + 4x - 1 = 0$
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$f ( x )=(3-\sin (2 \pi x )) \sin \left(\pi x -\frac{\pi}{4}\right)-\sin \left(3 \pi x +\frac{\pi}{4}\right)$
If $\alpha, \beta \in[0,2]$ are such that $\{x \in[0,2]: f(x) \geq 0\}=[\alpha, \beta]$, then the value of $\beta-\alpha$ is. . . . . . . . .