MCQ
The quantumuantum numbers $n = 2,\,\,l = 1$ represent
- A$1s$ orbital
- B$2s $ orbital
- ✓$2p $ orbital
- D$3d $ orbital
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$9\, mol$ $O_2$ and $14\, mol$ $N_2$ here allowed to react. When $3\, mol$ $O_2$ remains unreacted, till then how many moles of $N_2O_3$ would have been produced?
$CH_4\,(g)\,\,186.2\,JK^{-1}\,mol^{-1}$
$O_2\,(g)\,\,205.2\,JK^{-1}\,mol^{-1}$
$CO_2\,(g)\,\,213.6\,JK^{-1}\,mol^{-1}$
$H_2O\,(g)\,\,69. 9\,JK^{-1}\,mol^{-1}$
The entropy change $(\Delta S^o)$........$JK^{-1}\,mol^{-1}$ for the reaction
$CH_4\,(g) + 2O_2\,(g) \to CO_2\,(g) + 2H_2O(l)$ is
| Column-$I$ | Column-$II$ (Shape) |
| $(A) \,SF_4$ | $(1)$ Tetrahedral |
| $(B)\, BrF_3$ | $(2)$ Pyramidal |
| $(C)\, BrO_3^-$ | $(3)$ Sea-Saw shaped |
| $(D)\, NH_4^+$ | $(4)$ Bent $T-$ shaped |
$AB , A _2$ and $B _2$ are diatomic molecule. If the bond enthalpies of $A _2, B _2$ and $AB$ are in the ratio $1: 0.5: 1$, then the bond enthalpy of $A_2$ is $......\,kJ\,mol ^{-1}$ (Nearest integer)