MCQ
The radical, (image) is aromatic because it has
- A$7\, p-$orbitals and $7$ unpaired electrons
- B$6\, p-$orbitals and $7\,$ unpaired electrons
- ✓$6\, p-$orbitals and $6$ unpaired electrons
- D$7\, p-$orbitals and $6$ unpaired electrons.
✓
Answer
Correct option: C.
$6\, p-$orbitals and $6$ unpaired electrons
c
Benzyl free radical is aromatic as per Huckel's rule it has $6 \pi$ electreons present in $p-$orbital of carbon atoms involved in
Benzyl free radical is aromatic as per Huckel's rule it has $6 \pi$ electreons present in $p-$orbital of carbon atoms involved in
formation of benzene ring (Aromatic nature).
$6 \pi$ electrons and $6 p$ orbitals
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$E^o _{cell}$ for the cell :
→$Pt(s) |H_2(g)\,|\,HCOOH(aq.)\,||\,CH_3COOH(aq.)\,|\,H_2(g)|Pt(s)$
at $25\,^o C$ is ............ $\mathrm{V}$
$(K_a$ of $HCOOH \,= 2.4 × 10^{-4}$ , $K_a$ of $CH_3COOH = 1.8 × 10^{-5}$ , $log\,2\, = 0.3,\, log \,0.48, \frac{2.303 \times 298 \times R}{F} = 0.06)$
The correct order of second $I.E. $ of $C, N, O$ and $F$ are in the order
→Product $(A)$ obtained is
→Element of atomic number $23$ is placed in the periodic table in
→The number and type of bonds between two carbon atoms in $CaC_2$ are
→Phenol can be converted into salicylic acid by heating with
The correct order of reactivity of halogens is
Which among the following is a false statement
Carbon atoms in the compound ${(CN)_4}{C_2}$ are
→The magnetic moment of a transition metal compound has been calculated to be $3.87$ $B.M.$ The metal ion is
→