- A$(-3,1)$
- ✓$\left[-\frac{4}{3}, 2\right]$
- C$[1, \infty)$
- D$(-\infty,-1]$
$f'(x)=(4 a-3)(1)+(a-7) \cos x=0$
$\Rightarrow \quad \cos x=\frac{3-4 a}{a-7}$
$-1 \leq \frac{3-4 a}{a-7}<1$
$\frac{3-4 a}{a-7}+1 \geq 0$
$\frac{3-4 a+a-7}{a-7} \geq 0$
$\frac{-3 a-4}{a-7} \geq 0$
$\frac{3 a+4}{a-7} \leq 0$
$\frac{3-4 a}{a-7}<1$
$\frac{3-4 a}{a-7}-1<0$
$\frac{3-4 a-a+7}{a-7}<0$
$\frac{-5 a+10}{a-7}<0$
$\frac{5 a-10}{a-7}>0$
$\frac{5(a-2)}{a-7}>0$
$\alpha \in\left[-\frac{4}{3}, 2\right)$
Check end point $\left[-\frac{4}{3}, 2\right)$
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The objective function Z = 4x + 3y can be maximised subjected to the constraints 3x + 4y ≤ 24, 8x + 6y ≤ 48, x ≤ 5, y ≤ 6, x, y ≥ 0
$(A)$ $|\overrightarrow{ a }+\lambda \overrightarrow{ c }| \geq|\overrightarrow{ a }|$ for all $\lambda \in R$.
$(B)$ $\overrightarrow{ a }$ and $\overrightarrow{ c }$ are always parallel
$(4,2)$
$(A)$ $M^2$ $(B)$ $-N^2$ $(C)$ $-M^2$ $(D)$ $M N$