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STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium) — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)4 Marks
MCQ
The reaction $A(g) + 2B(g) \longrightarrow C(g) + D(g)$ is an elementary process. In an experiment, the initial partial pressure of $A$ and $B$ are $0.6$ and $0.8\, atm$, respectively. When partial pressure of $C$ is $0.2\, atm$, the rate of reaction relative to the initial rate is
  • A
    $1/48$
  • B
    $1/24$
  • C
    $9/16$
  • ✓
    $1/6$
✓

Answer

Correct option: D.
$1/6$
d
The expression for the initial rate is $\mathrm{r}_{0}=\mathrm{K}[\mathrm{A}][\mathrm{B}]^{2}=\mathrm{K}(0.60)(0.80)^{2} \ldots \ldots$ (1)

After some time, the pressure of $\mathrm{C}$ is $0.20 \mathrm{atm}$. Hence, the pressures of $A$ and $B$ are $0.60-0.20=0.40$ atm and $0.80-2(0.20)=0.40$ atm

respectively. The expression for the rate becomes $\mathrm{r}=\mathrm{k}[\mathrm{A}][\mathrm{B}]^{2}=\mathrm{K}(0.40)(0.40)^{2} \ldots . .$ ( $\left.2\right)$

Divide equation (2) with equation (1) $\frac{r_{o}}{r_{1}}=\frac{k[A][B]^{2}=K(0.60)(0.80)^{2}}{k[A][B]^{2}=K(0.40)(0.40)^{2}}=\frac{1}{6}$

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