MCQ
The reaction rate at a given temperature becomes slower, then
- ✓The free energy of activation is higher
- BThe free energy of activation is lower
- CThe entropy changes
- DThe initial concentration of the reactants remains constant
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$Cu^{2+}_{(aq)} + e^-\to Cu^+_{(aq)}$ and
$Cu^+_{(aq)} + e^-\to Cu_{(s)}$
are $+0.15\,V$ and $+0.50\,V$ respectively. The value of $E^o_{Cu^{2+}/Cu}$ will be ............ $\mathrm{V}$
$R - C \equiv C - R\xrightarrow{{Pd/BaS{O_4}}}A$
$R - C \equiv C - R\xrightarrow{{Na/Liq.\,NH_3}}B$