The reading of the ammeter as per figure shown is
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Resistance across $XY$ $ = \frac{2}{3}\,\Omega $
Total resistance
$ = 2 + \frac{2}{3} = \frac{8}{3}\,\Omega $
Current through ammeter
$ = \frac{2}{{8/3}} = \frac{6}{8} = \frac{3}{4}\,A$
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