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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
The reagent needed for converting

$Ph - C \equiv C - Ph \to $ 

  • A
    Cat. Hydrogenation
  • B
    $H_2/$ Lindlar Cat.
  • ✓
    $Li/NH_3$
  • D
    $LiAlH_4$
✓

Answer

Correct option: C.
$Li/NH_3$
c
With Lithium in liquid ammonia, trans-alkene is almost an exclusive product.

$Ph-C\equiv C-Ph\xrightarrow[Brich\,reduction]{Li\,in\,liq.N{{H}_{3}}}\begin{matrix}
   ^{Ph}  \\
   _{H}  \\
\end{matrix}\begin{matrix}
   \text{ }\!\!\backslash\!\!\text{ }  \\
   /  \\
\end{matrix}C=C\begin{matrix}
   /  \\
   \text{ }\!\!\backslash\!\!\text{ }  \\
\end{matrix}_{Ph}^{H}$

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Match List $I$ with List $II$

List $I$(Quantum Number) List $II$(Information provided)
$A$. mı $I$. Shape of orbital
$B$. $m_s$ $II$. Size of orbital
$C$. $1$ $III$. Orientation of orbital
$D$. $\mathrm{n}$ $IV$. Orientation of spin of electron

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