MCQ
The reagent that can distinguish benzaldehyde from propionaldehyde is
- A$I_2/NaOH$
- ✓Fehling's solution
- CTollens reagent
- D$2, 4-$ dinitrophenyl hydrazine
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Assertion $(A):$ $\mathrm{H}_2 \mathrm{Te}$ is more acidic than $\mathrm{H}_2 \mathrm{~S}$.
Reason $(R):$ The bond dissociation enthalpy of $\mathrm{H}_2 \mathrm{Te}$ is less than that of $\mathrm{H}_2 \mathrm{~S}$.
In the context of the above statements, choose the correct answer from the following options: