- A$p(H_2) = 1\,atm$ and $[H^+] = 2.0\,M$
- B$p(H_2) = 1\,atm$ and $[H^+] = 1.0\,M$
- ✓$p(H_2) = 2\,atm$ and $[H^+] = 1.0\,M$
- D$p(H_2) = 2\,atm$ and $[H^+] = 2.0\,M$
$E=E^{\circ}-\frac{0.059}{1} \log \frac{P_{H_{2}}^{1 / 2}}{\left|H^{+1}\right|}$
Now if $P_{H_{2}}=2$ atm and $\left[H^{+}\right]=1 M$
then $E=0-\frac{0.059}{1} \log \frac{2^{1 / 2}}{1}=-2$
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$Zn^{2+} + 2e^-$ $\longrightarrow$ $Zn (s) ; E^o = -0.76\,V$
$Ca^{2+} + 2e^-$ $\longrightarrow$ $Ca (s) ; E^o = -2.87\,V$
$Mg^{2+} + 2e^-$ $\longrightarrow$ $Mg (s) ; E^o = -2.36\,V$
$Ni^{2+} + 2e^-$ $\longrightarrow$ $Ni (s) ; E^o = -0.25\,V$
The reducing power of the metals increases in the order

$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$
If the total pressure of the gases is found to be $200$ torr after $23 \mathrm{sec}$. and $300$ torr upon the complete decomposition of $\mathrm{A}$ after a very long time, then the rate constant of the given reaction is . . . . . .$\times 10^{-2} \mathrm{~s}^{-1}$ (nearest integer)
[Given : $\log _{10}(2)=0.301$ ]
$C{H_3} - CH = CH - COOH\xrightarrow{{B{r_2}}}$