MCQ
The relation between Faraday constant $(F)$, chemical equivalent $(E)$ and electrochemical equivalent $(Z)$ is
- A$F = EZ$
- B$F = \frac{Z}{E}$
- ✓$F = \frac{E}{Z}$
- D$F = \frac{E}{Z^2}$
✓
Answer
Correct option: C.
$F = \frac{E}{Z}$
c
The relation between Faraday constant chemical equivalent and electrochemical equivalent is $F =\frac{ E }{ Z }$
The relation between Faraday constant chemical equivalent and electrochemical equivalent is $F =\frac{ E }{ Z }$
where $E$ is chemical equivalent, $Z$ is electrochemical equivalent and $F$ is faraday constant.
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