MCQ
The relation between Faraday constant (F), chemical equivalent (E) and electrochemical equivalent (Z) is
- AF = EZ
- B$F=\frac{Z}{E}$
- ✓$F=\frac{E}{Z}$
- D$F=\frac{E}{Z^2}$
✓
Answer
Correct option: C.
$F=\frac{E}{Z}$
(c) $F=\frac{E}{Z}$
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