MCQ
The relationship between force and position is shown in the figure $($in one dimensional case$)$. Work done by the force in displacing a body from
$X = 1\ cm$ to $X = 5\ cm$ is:
  • A
    $700$ ergs
  • B
    $70$ ergs
  • $60$ ergs
  • D
    $20$ ergs

Answer

Correct option: C.
$60$ ergs
Work is area under the curve.
So $\ce{In = In_1​ + In_2​ + In_3​ + In_4}​$
$\ce{In_1}=$ arandaundandr $\ce{A_1​BCM_2 In_2=}$ arandaundandr $\ce{M_2​DEF_3​}$
$\ce{In_3​} =$ arandaundandr $\ce{F_3​GHI_4 In_4=}$ arandaundandr $\ce{I_4​JKL_5}$
$\ce{In_1}​= 10 \times 1 = 10$ ergs
$\ce{In_2}​ = 20 \times 1 = 20$ ergs
$\ce{In_3}= −20 \times 1 = −20$ ergs
$\ce{In_4​} = 10 \times 1 = 10$ ergs
$\ce{In = In_1​ + In_2+ In_3​ + In_4}​ = 10 + 20 − 20 + 10 = 20$ ergs

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