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Mechanical Properties of Fluids — Physics STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsMechanical Properties of Fluids2 Marks
Question
The relative velocity between two layers of a fluid, separately by $0.1 \mathrm{~mm}$, is $2 \mathrm{~cm} / \mathrm{s}$. Calculate the velocity gradient.
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Answer


Data : dy $=0.1 \mathrm{~mm}=10^{-2} \mathrm{~cm}, \mathrm{dv}=2 \mathrm{~cm} / \mathrm{s}$
The velocity gradient, $\frac{d v}{d y}=\frac{2 \mathrm{~cm} / \mathrm{s}}{10^{-2} \mathrm{~cm}}=200 \mathrm{~s}^{-1}$

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