MCQ
The remainder, when $7^{103}$ is divided by $17$ is $..........$.
  • A
    $11$
  • $12$
  • C
    $13$
  • D
    $14$

Answer

Correct option: B.
$12$
b
$7^{103}=7 \times 7^{102}$

$=7 \times(49)^{51}$

$=7 \times(51-2)^{51}$

Remainder :- $7 \times(-2)^{51}$

$\Rightarrow-7\left(2^3 \cdot(16)^{12}\right)$

$\Rightarrow-56(17-1)^{12}$

$\text { Remainder }=-56 \times(-1)^{12}=-56+68=12$

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