The resistors of resistances $2$ $\Omega$, $4$ $\Omega$ and $8$ $\Omega$ are connected in parallel, then the equivalent resistance of the combination will be
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(a) $\frac{1}{{{R_{eq}}}} = \frac{1}{2} + \frac{1}{4} + \frac{1}{8} = \frac{{4 + 2 + 1}}{8}$ $ \Rightarrow $ ${R_{eq}} = \frac{8}{7}\,\Omega $.
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