MCQ
The salt that forms neutral solution in water is
- A$N{H_4}Cl$
- ✓$NaCl$
- C$N{a_2}C{O_3}$
- D${K_3}B{O_3}$
${H^ + }_{{\rm{(aq)}}} + C{l^ - }_{{\rm{(aq)}}} + N{a^ + }_{{\rm{(aq)}}} + O{H^ - }_{{\rm{(aq)}}} ⇌ {H_2}{O_{{\rm{(l)}}}} + N{a^ + }_{{\rm{(aq)}}} + C{l^ - }$
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| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{Cu}+$ dil $\mathrm{HNO}_3$ | $(p)$ NO |
| $(B)$ $\mathrm{Cu}+$ conc $\mathrm{HNO}_3$ | $(q)$ $\mathrm{NO}_2$ |
| $(C)$ $\mathrm{Zn}+$ dil $\mathrm{HNO}_3$ | $(r)$ $\mathrm{N}_2 \mathrm{O}$ |
| $(D)$ $\mathrm{Zn}+$ conc $\mathrm{HNO}_3$ | $(s)$ $\mathrm{Cu}\left(\mathrm{NO}_3\right)_2$ |
| $(t)$ $ \mathrm{Zn}\left(\mathrm{NO}_3\right)_2$ |
Reason $R : I^{-1}$ is a good nucleophile as well as a good leaving group.
In the light of the above statements, choose the correct answer from the options given below.
$(1) Ca_3P_2 + H_2O \to$
$(2)$ ${H_3}P{O_3}\xrightarrow{\Delta }$
$(3) P_4 + NaOH \to$
$(4)$ ${H_3}P{O_4}\xrightarrow{\Delta }$
$(5) HNO_3 + P_4O_{10} \to$
$(6)$ $P_4+HNO_3 \to$