Question
 The same amount of electricity was passed through two separate electrolytic cells containing solutions of nickel nitrate and chromium nitrate respectively. If 2.935 g of Ni was deposited in the first cell. The amount of Cr deposited in the another cell?
Given: molar mass of Nickel and chromium are 58.74 and $52 gm ^{-1}$ respectively.

Answer

$
\begin{aligned}
& Ni _{( aq )}^{2+}+2 e ^{-} \longrightarrow Ni _{( s )} \\
& Cr _{( aq )}^{2+}+3 e ^{-} \longrightarrow Cr _{( s )}
\end{aligned}
$
The above reaction indicates that a $2 F$ charge is required to deposit $58.7 g$ of Nickel from nickel nitrate and $3 F$ charge is required to deposit $52 g$ of chromium.
Given that 2.935 gram of Nickel is deposited
$
\begin{aligned}
& \therefore \text { The amount of charge passed through the cell }=\frac{2 F }{58.7 g } \times 2.935 g \\
& =0.1 F
\end{aligned}
$
$\therefore$ If $0.1 F$ charge is passed through chromium nitrate the amount of chromium deposited
$
\begin{aligned}
& =\frac{52 g }{3 F } \times 0.1 F \\
& =1.733 g
\end{aligned}
$

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