- A$21,32,53,64$
- ✓$21,25,42,72$
- C$9,17,34,38$
- D$37,42,50,64$
$37$ to $48$
$57$ $\&$ $72$ to $80$
Ans. $21,25,42\, \& 72$
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$HCHO\xrightarrow[{dil{H_2}S{O_4}}]{{NaCN}}A\xrightarrow[{\operatorname{P} t}]{{{H_2}}}B$ The product $(B)$ is
Temperature $\quad$ Equilibrium constant
$\begin{array}{ll} T _{1}=25^{\circ} C & K _{1}=100 \\ T _{2}=100^{\circ} C & K _{2}=100\end{array}$
The values of $\Delta H ^{\circ}, \Delta G ^{\circ}$ at $T _{1}$ and $\Delta G ^{\circ}$ at $T _{2}$ (in $kJ\, mol ^{-1}$ ) respectively, are close to $\left[\right.$ Use $\left. R =8.314\, JK ^{-1} mol ^{-1}\right]$
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The correct option is
$\Delta E = - 2.0 \times {10^{ - 18}}\,J\left( {\frac{1}{{n_2^2}} - \frac{1}{{n_1^2}}} \right)$
the wavelength of the light that must be absorbed to excite hydrogen electron from level $n\, = 1$ to level $n\, = 2$ will be: $(h\, = 6.625\times10^{-34}\, J\,s,\, C\, = 3\times10^8\, m\,s^{-1})$