1) $\mathrm{m}_1=\frac{180}{60}=3, \mathrm{i}=1+\alpha$
Hence
$\Delta \mathrm{T}_{\mathrm{f}}=(1+\alpha) \cdot \mathrm{k}_{\mathrm{f}}=3 \times 1.86=5.58^{\circ} \mathrm{C}(\alpha<<1)$
$2)$ $\mathrm{m}_2=\frac{180}{60}=3, \mathrm{i}=0.5, \Delta \mathrm{T}_{\mathrm{f}}=\frac{3}{2} \times \mathrm{k}_{\mathrm{f}}{ }^{\prime}=7.68^{\circ} \mathrm{C}$
3) $\mathrm{m}_3=\frac{180}{122}=1.48, \mathrm{i}=0.5, \Delta \mathrm{T}_{\mathrm{f}}=\frac{1.48}{2} \times \mathrm{k}_{\mathrm{f}}^{\prime}=3.8^{\circ} \mathrm{C}$
4) $\mathrm{m}_4=\frac{180}{180}=1, \mathrm{i}=1, \Delta \mathrm{T}_{\mathrm{f}}=1 \cdot \mathrm{k}_{\mathrm{f}}^{\prime}=1.86^{\circ} \mathrm{C}$
As per NCERT, $\mathrm{k}_{\mathrm{f}}{ }^{\prime}\left(\mathrm{H}_2 \mathrm{O}\right)=1.86 \mathrm{k} \cdot \mathrm{kg} \mathrm{mol}^{-1}$
$\mathrm{k}_{\mathrm{f}}{ }^{\prime}($ Benzene $)=5.12 \mathrm{k} \cdot \mathrm{kg} \mathrm{mol}^{-1}$
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|
${List-I }$ ${(Reactants) }$ |
${List-II }$ ${ Products }$ |
| ($A$)Phenol, $\mathrm{Zn} / \Delta$ |
$(I)$ Salicylaldehyde |
| ($B$)Phenol, $\mathrm{CHCl}_3, \mathrm{NaOH}, \mathrm{HCl}$ |
$(II)$ Salicylic acid |
| ($C$)Phenol, $\mathrm{CO}_2, \mathrm{NaOH}, \mathrm{HCl}$ |
$(III)$ Benzene |
| ($D$)Phenol, Conc. $\mathrm{HNO}_3$ |
$(IV)$ Picric acid |
