MCQ
The solution of $\frac{{dy}}{{dx}} = {e^x}(\sin x + \cos x)$ is
- A$y = {e^x}(\sin x - \cos x) + c$
- B$y = {e^x}(\cos x - \sin x) + c$
- ✓$y = {e^x}\sin x + c$
- D$y = {e^x}\cos x + c$
==> $dy = {e^x}(\sin x + \cos x)dx$
On integrating, we get $y = {e^x}\sin x + c$.
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| $X = x_i$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ |
| $P(X = X_i)$ | $0$ | $2p$ | $2p$ | $3p$ | $p^2$ | $2p^2$ | $7p^2$ | $2p$ |