MCQ
The solution of ${e^{2x - 3y}}dx + {e^{2y - 3x}}dy = 0$ is
- ✓${e^{5x}} + {e^{5y}} = c$
- B${e^{5x}} - {e^{5y}} = c$
- C${e^{5x + 5y}} = c$
- DNone of these
Multiply the equation by ${e^{3x + 3y}}$ ==> ${e^{5x}}dx + {e^{5y}}dy = 0$
On integrating, we get ${e^{5x}} + {e^{5y}} = 5c' = c$.
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$f(x)=\min \{x-[x], 1+[x]-x\}$
where $[\mathrm{x}]$ is the greatest integer less than or equal to $\mathrm{x}$. Let $\mathrm{P}$ denote the set containing all $x \in[0,3]$ where $f$ is discontinuous, and $Q$ denote the set containing all $x \in(0,3)$ where $f$ is not differentiable. Then the sum of number of elements in $\mathrm{P}$ and $\mathrm{Q}$ is equal to $......$