MCQ
The solution of inequality $-x^2+3 x-2>0$ is :
- A$(-1,2)$
- B$(2,1)$
- ✓$(1,2)$
- D$(2,-1)$
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The negation of the statement “The product of 3 and 4 is 9” is.
The distance between the lines y = mx + c1 and y = mx + c2 is:
$\frac{\text{c}_1-\text{c}_2}{\sqrt{\text{m}^2+1}}$
$\frac{|\text{c}_1-\text{c}_2|}{\sqrt{1+\text{m}^2}}$
$\frac{\text{c}_2-\text{c}_1}{\sqrt{1+\text{m}^2}}$
$0$