MCQ
The solution of the differential equation $\frac{dy}{dx}= \frac{y}{(y^2-x)}$ is
- A$y^3 -xy = c$
- ✓$y^3 -3xy = c$
- C$y^3 + 3xy = c$
- D$y^3 + xy = c$
$\therefore $ solution is $x . y=\int y^{2} d y+c \Rightarrow x . y=\frac{y^{3}}{3}+c$
$\Rightarrow \mathrm{y}^{3}-3 \mathrm{xy}=\mathrm{c}$
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Maximize $z=2 x+3 y$ the coordinates of the corner points of the bounded feasible region are $A\,(3,3), B\,(20,3),$ $\mathrm{C}\,(20,10), \mathrm{D}\,(18,12)$ and $\mathrm{E}\,(12,12) .$ The maximum value of $z$ is $\ldots \ldots$