MCQ
The solution of the differential equation $\frac{{dy}}{{dx}} = \sec x(\sec x + \tan x)$is
- ✓$y = \sec x + \tan x + c$
- B$y = \sec x + \cot x + c$
- C$y = \sec x - \tan x + c$
- DNone of these
Now integrating both sides, we get $y = \tan x + \sec x + c$.
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$(A)$ $f(x)$ is monotonically increasing on $[1, \infty)$
$(B)$ $f(x)$ is monotonically decreasing on $(0,1)$
$(C)$ $f(x)+f\left(\frac{1}{x}\right)=0$, for all $x \in(0, \infty)$
$(D)$ $f\left(2^x\right)$ is an odd function of $x$ on $R$