MCQ
The solution of the linear equation x + 2y = 8 which represents a point on y-axis, is
- A(0,4)
- B(8,0)
- C(4,2)
- D(2, 3)
✓
Answer
A. (0, 4)
Let $(0, a)$ be a point on $y$-axis representing a solution of the equation. Then, $x=0$ and $y=a$ is a solution of equation $x+2 y=8$.
$\therefore$ $0+2 a=8 \Rightarrow a=4
$
Hence, $(0,4)$ is the required point.
Let $(0, a)$ be a point on $y$-axis representing a solution of the equation. Then, $x=0$ and $y=a$ is a solution of equation $x+2 y=8$.
$\therefore$ $0+2 a=8 \Rightarrow a=4
$
Hence, $(0,4)$ is the required point.
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