Download App

STD 12 - 3 and 4 . determinant and metrices — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 3 and 4 . determinant and metrices1 Mark
MCQ
The solution $(s)$ of the equation $\left| {\begin{array}{*{20}{c}}x&a&b\\ a&x&a\\b&b&x\end{array}} \right|$ $= 0$ is/are :
  • A
    $x = - (a + b)$
  • B
    $x = a$
  • C
    $x = b$
  • ✓
    All of the above
✓

Answer

Correct option: D.
All of the above
d
Use $c_1 \rightarrow c_1 -c_2$ and then $R_1 \rightarrow R_1 + R_2 $ to get $\left| {\,\begin{array}{*{20}{c}}0&{a + x}&{b + a}\\{ - (x - a)}&x&a\\0&b&x \end{array}\,} \right|$ $= 0$. Now open by $c_1$ and foctorize

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 3 and 4 . determinant and metrices→STD 12 - 3 and 4 . determinant and metrices — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

The distance of point $(1, 2, 3)$ from origin is
→
If $A = \left[ {\begin{array}{*{20}{c}}3&{ - 3}&4\\2&{ - 3}&4\\0&{ - 1}&1\end{array}} \right]$, then ${A^{ - 1}}$=
→
Let $A$ and $B$ be two $3 \times 3$ non-zero real matrices such that $AB$ is a zero matrix. Then.
→
For the multiplication of matrices as a binary operation on the set of all matrices of the form $\begin{bmatrix}\text{a}&\text{b}\\-\text{b}&\text{a}\end{bmatrix},\text{a, b}\in\text{R}$ the inverse of $\begin{bmatrix}2&3\\-3&2\end{bmatrix}$ is:
→
Let $\vec{a}$ be a vector which is perpendicular to the vector $3 \hat{ i }+\frac{1}{2} \hat{ j }+2 \hat{ k }$. If $\overrightarrow{ a } \times(2 \hat{ i }+\hat{ k })=2 \hat{ i }-13 \hat{ j }-4 \hat{ k }$, then the projection of the vector $\vec{a}$ on the vector $2 \hat{ i }+2 \hat{ j }+\hat{ k }$ is
→
If $\text{A} = \begin{bmatrix}\cos\alpha&-\sin\alpha\\ \sin\alpha&\cos\alpha\end{bmatrix},\text{then}\ \text{A + A}'=\text{I}$, if the value of a is:
→
The value of ${d \over {dx}}[|x - 1| + |x - 5|]$ at $x = 3$ is
→
Let $\vec{a}=2 \hat{i}+5 \hat{j}-\hat{k}, \vec{b}=2 \hat{i}-2 \hat{j}+2 \hat{k}$ and $\overrightarrow{\mathrm{c}}$ be three vectors such that $(\vec{c}+\hat{i}) \times(\vec{a}+\vec{b}+\hat{i})=\vec{a} \times(\vec{c}+\hat{i}) \cdot \vec{a} \cdot \vec{c}=-29$, then $\overrightarrow{\mathrm{c}} \cdot(-2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}})$ is equal to :
→
If $C$ and $D$ are two events such that $P\left( D \right) \ne 0$ then the correct statement among the following is
→
An urn contains $5$ red and $2$ black balls. Two balls are randomly drawn. Let $X$ represent the number of black balls. What are the possible values of $X?$ Is $X$ a random variable?
→