The solution set of |x-1|+|x+1|<2 is - Vidyadip

MCQ

The solution set of $|x-1|+|x+1|<2$ is

A
$(-1,1)$
B
$[-1,1]$
✓
$\phi$
D
$\{-1,1\}$

✓

Answer

Correct option: C.

$\phi$

c

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The area bounded by curves $y = \cos x$ and $y = \sin x$ and ordinates $x = 0$ and $x = \frac{\pi }{4}$ is

Let $(\alpha, \beta, \gamma)$ be the point $(8,5,7)$ in the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-2}{5}$. Then $\alpha+\beta+\gamma$ is equal to

Twenty persons arrive in a town having $3$ hotels $x, y$ and $z$. If each person randomly chooses one of these hotels, then what is the probability that atleast $2$ of them goes in hotel $x$, atleast $1$ in hotel $y$ and atleast $1$ in hotel $z$ ? (each hotel has capacity for more than $20$ guests)

The value of $\left( \begin{array}{l}30\\0\end{array} \right)\,\left( \begin{array}{l}30\\10\end{array} \right) - \left( \begin{array}{l}30\\1\end{array} \right)\,\left( \begin{array}{l}30\\11\end{array} \right)$ + $\left( \begin{array}{l}30\\2\end{array} \right)\,\left( \begin{array}{l}30\\12\end{array} \right) + ....... + \left( \begin{array}{l}30\\20\end{array} \right)\,\left( \begin{array}{l}30\\30\end{array} \right)$

Let $2^{\text {nd }}, 8^{\text {th }}$ and $44^{\text {th }}$, terms of a non-constant $A.P.$ be respectively the $1^{\text {st }}, 2^{\text {nd }}$ and $3^{\text {rd }}$ terms of $G.P.$ If the first term of $A.P.$ is $1$ then the sum of first $20$ terms is equal to-

A bar of length $20 $ units moves with its ends on two fixed straight lines at right angles. $A $ point $P $ marked on the bar at a distance of $ 8$ units from one end describes a conic whose eccentricity is

$A(0,2)$ and $C(6,4)$ are opposite vertices of square $ABCD$. Sum of slopes of sides through vertex $A$ will be-

$\int_{}^{} {\frac{{{a^x}}}{{\sqrt {1 - {a^{2x}}} }}dx = } $

If the components of $\overrightarrow{ a }=\alpha \hat{ i }+\beta \hat{ j }+\gamma \hat{ k }$ along and perpendiculer to $\overrightarrow{ b }=3 \hat{ i }+\hat{ j }-\hat{ k }$ respectively, are $\frac{16}{11}(3 \hat{ i }+\hat{ j }-\hat{ k })$ and $\frac{1}{11}(-4 \hat{ i }-5 \hat{ j }-17 \hat{ k })$, then $\alpha^2+\beta^2+\gamma^2$ is equal to :

Let $\alpha, \beta$ be the roots of the equation $x^2-\sqrt{2} x+2=0$. Then $\alpha^{14}+\beta^{14}$ is equal to