MCQ
The species having bond order different from that in $\mathrm{CO}$ is
- ✓$\mathrm{NO}^{-}$
- B$\mathrm{NO}^{+}$
- C$\mathrm{CN}^{-}$
- D$\mathrm{N}_2$
Bond order $=2$.
$\mathrm{NO}^{\oplus}, \mathrm{CN}^{-}$and $\mathrm{N}_2$ are isoelectronic with $\mathrm{CO}$ therefore all have same bond order $(=3)$
Hence ($A$) is correct.
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Reason : The presence of additional $d-$ electron offer poor screening effect for the outer electrons from increased nuclear charge.
| Column $-I$ (various solutions) |
Column $-II$ (Their freezing point ) |
||
| $a$ | $0.1\,M$ $BaCl_2$ solution | $p$ | $271\,K$ |
| $b$ | $0.1\,M$ $NaCl$ solution | $q$ | $270\,K$ |
| $c$ | $0.1\,M\, K_3 [Fe(CN)_6]$ solution | $r$ | $268\,K$ |
| $d$ | $0.1\,M\, Al_2 (SO_4)_3$ solution | $s$ | $269\,K$ |
Given : Freezing point of $0.1\,M$ sucrose solution $= 272\,K$ and $F.pt.$ of water $= 273\,K$
Which of the following option show correct matches ?