MCQ
The species having bond order different from that in $\mathrm{CO}$ is
- ✓$\mathrm{NO}^{-}$
- B$\mathrm{NO}^{+}$
- C$\mathrm{CN}^{-}$
- D$\mathrm{N}_2$
Bond order $=2$.
$\mathrm{NO}^{\oplus}, \mathrm{CN}^{-}$and $\mathrm{N}_2$ are isoelectronic with $\mathrm{CO}$ therefore all have same bond order $(=3)$
Hence ($A$) is correct.
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$(i)\,\,C\,({\rm{graphite}})\, + \,{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = x\,\,kJ\,mo{l^{ - 1}}$
$(ii)\,\,C\,({\rm{graphite}})\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,CO\,(g);\,\Delta r{H^\circleddash} = y\,\,kJ\,mo{l^{ - 1}}$
$(iii)\,\,CO\,(g)\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = z\,\,kJ\,mo{l^{ - 1}}$
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
If dilute $HCl$ is added to an aqueous solution of ${H_2}S$ without any change in temperature