Question
The standard electrode potential $(E^\circ)$ for Deniell cell is $+1.1V.$ Calculated the $ʌG^\circ$ for the reaction
$Zn (s) + Cu^{2+ }(aq) \rightarrow Zn^{2 }(aq) + Cu (s)$
$(1 F = 96500\ C\ mol^{-1}).$

Answer

$\triangle G^\circ = -n FE^\circ$ cell
$= -2 \times 96500\ C\ mol^{-1} \times 1.1\ V$
$= -212300\ J\ mol^{-1}$ or $-212.3\ k\ J\ mol^{-1}$

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