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2. Electrochemistry — Chemistry STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceChemistry2. Electrochemistry1 Mark
MCQ
The standard electrode potentials

${E^o}_{\left( {{I_2}/{I^ - }} \right)},{E^ \circ }_{\left( {Br^-/B{r_2}} \right)}$ and ${E^ o }_{\left( {{Fe}/{Fe^{2+} }} \right)}$

are respectively $+ 0.54\  V$, $-1.09\  V$ and $0.44\  V$. On the basis of above data which of the following process is non-spontaneous

  • A
    $B{r_2} + 2{I^ - } \to 2B{r^ - } + {I_2}$
  • B
    $Fe + B{r_2} \to F{e^{2 + }} + 2B{r^ - }$
  • C
    $Fe + {I_2} \to F{e^{2 + }} + 2{I^ - }$
  • ✓
    ${I_2} + 2B{r^ - } \to 2{I^ - } + B{r_2}$
✓

Answer

Correct option: D.
${I_2} + 2B{r^ - } \to 2{I^ - } + B{r_2}$
d
For   ${{\text{I}}_{2}}+2\text{B}{{\text{r}}^{-}}\to 2{{I}^{-}}+\text{B}{{\text{r}}_{2}}$

$\text{E}_{\text{cell }}^{o}=\left( \text{E}_{\text{Rp}}^{{}^o } \right)\text{ cathode }-{{\left( \text{E}_{\text{RP}}^{{}^o } \right)}_{\text{anode }}}$

$\because \,\,\,\text{E}_{\text{cell}}^{o}$ is negative hence this reaction is non-spontaneous

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