MCQ
The structure of $4-$ methyl pentene $-2$ is
- A${(C{H_3})_2}CH - C{H_2}CH = C{H_2}$
- ✓${(C{H_3})_2}CH - CH = CH - C{H_3}$
- C${(C{H_3})_2}CH - C{H_2}CH = CH - C{H_3}$
- D${(C{H_3})_2}C = CHC{H_2}C{H_3}$
$\left( CH _3\right)_2 CH - CH _2 CH = CH _2$ is named as $4$-methyl pent-$1$-ene.
$\left( CH _3\right)_2 CH - CH _2- CH = CH - CH _3$ is named as $5$-methyl hex-$2$-ene.
$\left( CH _3\right)_2 C = CH - CH _2- CH _3$ is named as $4$-methyl pent-$3$-ene.
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$(I) \,C_6H_5CH_3$
$(II)\, C_6H_5COOH$
$(III)\, C_6H_6$
$(IV) \,C_6H_5NO_2$
$Y$ is
$X + \frac{1}{2}{O_2}\,\, \to \,\,XO + 90.8\,kJ$
It follows that the heat of reaction for the following process $M + XO$ $\rightleftharpoons$ $MO + X$ is given by......$kJ$
$ NH_3(g) \rightleftharpoons \frac{1}{2}\,{N_2}\left( g \right) + \frac{3}{2}{H_2}\left( g \right);\,{K_2}$
$\frac{1}{2}\,{N_2}\left( g \right) + \frac{3}{2}{H_2}\left( g \right) \rightleftharpoons NH_3(g); K_3$
$2NH_3(g) \rightleftharpoons N_2(g) + 3H_2(g); K_4$
If $K_1 = K_2^x = K_3^y = K_4^z$ then correct values of $x, y$ and $z$ are respectively
End product of the reaction is