$2c - 2e:H - B - H$
$\begin{array}{*{20}{c}}
{^H} \\
{_H}
\end{array}\begin{array}{*{20}{c}}
\backslash \\
/
\end{array}B\begin{array}{*{20}{c}}
/ \\
\backslash
\end{array}_H^H\begin{array}{*{20}{c}}
\backslash \\
/
\end{array}B\begin{array}{*{20}{c}}
/ \\
\backslash
\end{array}_H^H$
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$\begin{matrix}
\begin{matrix}
\,\,\,\,\,C{{H}_{3}} \\
| \\
\end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}C{{H}_{2}}OH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $\xrightarrow[{{H_2}O,heat}]{{{K_2}C{r_2}{O_7};{H_2}S{O_4}}}A$ $\xrightarrow{{SOC{l_2}}}B\xrightarrow[{(2{\kern 1pt} mole)}]{{{{(C{H_3})}_2}NH}}C$ $\xrightarrow[{2.{\kern 1pt} {H_2}O}]{{\begin{array}{*{20}{c}}
{1.{\kern 1pt} LiAl{H_4}} \\
{diethyl{\kern 1pt} {\kern 1pt} ether}
\end{array}}}D$
$C$ $ (graphite) $ $ + {O_2}(g) \to C{O_2}(g);\,\Delta H = - 393.5$
If the graphite is made of diamond then the above figure is $\Delta H$.......$kJ$