STD 11 - 4. Chemical bonding and molecular structure — NEET STD 11 Science — Question

It can be depicted as follow

$(z=53)($ Ground state $)=$

$\mathop {\boxed{ \uparrow  \downarrow }}\limits^{5s} \,\,\mathop {\boxed{ \uparrow  \downarrow }\boxed{ \uparrow  \downarrow }\boxed \uparrow }\limits^{5p} \,\,\mathop {\boxed{}\boxed{}\boxed{}\boxed{}\boxed{}}\limits^{5d} $

$I$ (Excited state) =

$\mathop {\boxed \uparrow }\limits^{5s} \,\,\mathop {\boxed \uparrow \boxed \uparrow \boxed \uparrow }\limits^{5p} \,\,\mathop {\boxed \uparrow \boxed \uparrow \boxed \uparrow \boxed{}\boxed{}}\limits^{5d} $

$I{F_7} = \mathop {\boxed{ \uparrow  \times }}\limits^{5s} \,\,\mathop {\boxed{ \uparrow  \times }\boxed{ \uparrow  \times }\boxed{ \uparrow  \times }}\limits^{5p} \,\,\mathop {\boxed{ \uparrow  \times }\boxed{ \uparrow  \times }\boxed{ \uparrow  \times }\boxed{}\boxed{}}\limits^{5d} $

                    $s p^{3} d^{3}$ -hybridisation

Here, $X$ denotes electrons of $F$ -atoms. The structure of $I F_{7}$ is shown below:

(fig.)

Pentagonal bipyramidal structure