MCQ
The structure of the noble gas compound $XeF_4$ is
- ✓square planar
- Bdistoned tetrahedral
- Ctetrahedral
- Doctahedral
so, it has square planar structure
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$C{O_{2(s)}} + {H_{2(g)}} \rightleftharpoons C{O_{(s)}} + {H_2}O(g)\,;\,{K_1}$
$C{O_{2(s)}} + CO(g) \rightleftharpoons C{O_{(s)}} + C{O_2}(g)\,;\,{K_2}$
Calculate the equilibrium for the reaction
$C{O_{2(s)}} + {H_2}(g) \rightleftharpoons CO(g) + {H_2}O(g)\,$
$(x)\begin{array}{*{20}{c}}
{O\,\,\,}\\
{||\,\,\,}\\
{C{H_3} - S - O - H}\\
{||\,\,\,\,}\\
{O\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,O}\\
{\,\,\,\,\,\,||}\\
{(y)\,\,\,C{H_3} - C - O - H}
\end{array}$
$(z)\,\, CH_3 -OH$