The sum of first 40 positive integers divisible by 6 is : - Vidyadip

MCQ

The sum of first $40$ positive integers divisible by $6$ is :

A
$2460$
B
$3640$
✓
$4920$
D
$4860$

✓

Answer

Correct option: C.

$4920$

The frist $40$ positive numbers divisible by $6$ will be
$\{6, 12, 18, 24, ......\}$
Here,
$a = 6$
$d = 6$
$n = 40$
$\text{S}_\text{n}=\frac{\text{n}}{2}\big[2\text{a}+(\text{n}-1)\text{d}\big]$
$\Rightarrow\text{S}_{40}=\frac{40}{2}\big[2(6)+39(6)\big]$
$\Rightarrow\text{S}_{40}=20[12+234]$
$\Rightarrow\text{S}_{40}=20[246]$
$\Rightarrow\text{S}_{40}=4920$

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