MCQ
The system $x - 2y = 3$ and $3x + ky = 1$ has a unique solution only when:
- A$\text{k}=-6,$
- ✓$\text{k}\neq-6$
- C$\text{k}=0$
- D$\text{k}\neq0$
$x-2 y=3 \text { and } 3 x+k y=1$
We know that, the system of linear equations $a_1 x+b_1 x+c_1=0, a_2 x+b_2 y+c_2=0$
has a unique solution if $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$.
$\text { So, } \frac{1}{3} \neq \frac{-2}{k}$
$\Rightarrow k \neq-6$
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