MCQ
The temperature of the system decreases in an
- AAdiabatic compression
- BIsothermal compression
- CIsothermal expansion
- ✓Adiabatic expansion
✓
Answer
Correct option: D.
Adiabatic expansion
(d)When a real gas is forced through a porous plug into a region of low pressure, it is found that due to expansion, the gas on the side of low pressure gets cooled.
The phenomenon of producing lowering of temperature when a gas is made to expand adiabatically from a region of high pressure into a region of low pressure is known as Joule-Thomson effect.
The phenomenon of producing lowering of temperature when a gas is made to expand adiabatically from a region of high pressure into a region of low pressure is known as Joule-Thomson effect.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Two equilibria, $AB \rightleftharpoons {A^ + } + {B^ - }$ and $AB + {B^ - } \rightleftharpoons AB_2^ - $ are simultaneously maintained in a solution with equilibrium constants, $K_1$ and $K_2$ respectively. The ratio of $[A^+]$ to $[AB_2^-]$ in the solution is
→$NaHSO_3$ is heated to produce $H_2O$ and compound $'A'$ . Which of the following statement is $INCORRECT$ about $'A'$
→In the neutral or faintly alkaline medium, $KMnO _{4}$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from?
→Which of the following statements about ${H_3}B{O_3}$ is not correct
→Which of the following reaction is correct?
Number of benzene derivatives of $C_7H_7Cl$ is :
→(image) An alkene (major)
A ball weighing $10 \,g$ is moving with a velocity of $90\, ms ^{-1}$. If the uncertainty in its velocity is $5\, \%$, then the uncertainty in its position is ....... $\times 10^{-33} \,m$. (Rounded off to the nearest integer) [Given : $\left. h =6.63 \times 10^{-34} \,Js \right]$
→If energy of the electron in hydrogen atom in some excited state is $-3.4\,eV,$ then what will be its angular momentum
→For a cell involving one electron $E_{cell }^{\ominus} =0.59 \mathrm{V}$ at $298 \;\mathrm{K}$, the equilibrium constant for the cell reaction is
→Given that $\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{V} \text { at } \mathrm{T}=298 \mathrm{K}\right]$