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The time period of a simple pendulum is $2\, sec$. If its length is increased $4$ times, then its period becomes  ..... $\sec$
AIPMT 1999, Easy
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(d) $T \propto \sqrt l $

==> $\frac{{{T_1}}}{{{T_2}}} = \sqrt {\frac{{{l_1}}}{{{l_2}}}} $

==> $\frac{2}{{{T_2}}} = \sqrt {\frac{l}{{4l}}} $

==> ${T_2} = 4\,sec$

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