The total energy of a particle, executing simple harmonic motion … - Vidyadip

MCQ

The total energy of a particle, executing simple harmonic motion is

A
$ \propto x$
B
$ \propto {x^2}$
✓
Independent of$x$
D
$ \propto {x^{1/2}}$

✓

Answer

Correct option: C.

Independent of$x$

c
(c)Total energy $ = \frac{1}{2}m{\omega ^2}{a^2}$= constant

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